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Question

Calculate the enthalpy change accompaying the conversion of 10 grams of graphite into diamond if the standard enthalpy of combustion of Cgraphite and Cdiamond are -94.05 and -94.50 kcal respectively.

A
0.45 kcal
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B
-0.45 kcal
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C
-0.375 kcal
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D
0.375 kcal
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Solution

The correct option is D 0.375 kcal
Given that
(i) Cgraphite+O2(g)CO2(g);ΔH=94.05kcal
(ii) Cdiamond+O2(g)CO2(g);ΔH=94.50kcal
Thus applying the inspection method [Eq. (i) - Eq. (ii)], we get

CgraphiteCdiamond;ΔH=0.45 kcal
Since this enthalpy change is only for conversion of 1 mol i.e. 12 g of Cgraphite to Cdiamond, therefore, for the converion of 10 g of Cgraphite to Cdiamond
ΔH=0.45×1012
=0.375 kcal

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