CameraIcon

SearchIcon

MyQuestionIcon

3

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Hess' Law

Calculate the...

Question

Calculate the enthalpy of the reaction:
$S n O_{2} (s) + 2 H_{2} (g) ⟶ S n (s) + 2 H_{2} O (l)$
given that, enthalpies of formation of $S n O_{2} (s)$ and $H_{2} O (l)$ are $- 580.7 k J$ and $- 285.8 k J$ respectively.

A

- 9.1 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

+ 9.1 k J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

- 8.1 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

+ 8.1 k J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $+ 9.1 k J$
Enthalpy of reaction = 2 $\times$ enthalpy of fromation of water - enthalpy of formation of $S N O_{2}$
Enthalpy of reaction = $2 * (- 285.8) - (- 580.7) = 9.1 k J$

Suggest Corrections

thumbs-up

0

Similar questions

Δ H_{l a t t i c e}

S n O_{2}

Δ H_{f}

S n O_{2}

is -588 KJ / mol, Enthalpy of Sublimation (Sn) = 292 KJ / mol, Enthalpy of Dissociation

(O_{2}) = 454 K J / m o l

. Total Electron gain enthalpy for O = 636 KJ / mol, Ionization enthalpy

(S n \to S n^{4 +})

= 8990 kJ / mol.

Q. Calculate the enthalpy change for the following reaction:

{C H}_{4} (g) + 2 O_{2} (g) ⟶ {C O}_{2} (g) + 2 H_{2} O (l)

Given, enthalpies of formation of

{C H}_{4}, {C O}_{2}

H_{2} O

74.8 k J {m o l}^{- 1}, - 393.5 k J {m o l}^{- 1}, - 286 k J {m o l}^{- 1}

Q. The standard enthalpy of formation of octane

(C_{8} H_{18})

- 250 kJ/mol

. Calculate the enthalpy of combustion of

C_{8} H_{18}

. Given that enthalpy of formation of

C O_{2} (g)

H_{2} O (l)

- 394 kJ/mol

- 286 kJ/mol

Q. Change in enthalpy for the reaction,

2 H_{2} O_{2} (l) \to 2 H_{2} O (l) + O_{2} (g)

, if heat of formation of

H_{2} O_{2} (l)

H_{2} O (l)

- 188

- 286 k J / m o l

respectively is:

Q. The enthalpy of combustion of one mole of benzene, carbon and hydrogen are

- 3267 k J / m o l, - 393.5 k J / m o l

- 285.8 k J / m o l

respectively. Calculate the standard enthalpy of formation of benzene.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Thermochemistry

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon