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Third Law of Thermodynamics

Calculate the...

Question

Calculate the entropy increase in the evaporation of 1 mole of a liquid when it boils at $100^{0} C$ having heat of vapourisation at $100^{0} C$ as 540 Cal/gm.

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Solution

Heat of vapourisation at $100^{0} C = 540$ Cal/gm
Molar heat of vapourisation $= 540 \times 18$ Cal/gm
$Δ S = \frac{q_{r e v}}{T} = \frac{540 \times 18}{373}$
$Δ S = 26.06$ Cal/gm

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