Calculate the equilibrium concentration of B+ ions in a solution obtained by mixing equal volume of 0.02 M AOH and 0.2 M BOH solution.
Given that,
Kb(AOH)=1×10−8
Kb(BOH)=2×10−9
For AOH :
AOH(aq)⇌OH−(aq)+ A+(aq)
at t=0 C1 0 0
at t=teq C1−C1α1 (C1α1+C2α2) C1α1
For BOH :
BOH(aq)⇌OH−(aq)+ B+(aq)
at t=0 C1 0 0
at t=teq C2−C2α2 (C1α1+C2α2) C2α2