Calculate the equilibrium constant for the following reaction:
$C u (s) + 2 {A g}^{+} (a q .) ⇌ {C u}^{2 +} (a q) + 2 A g (s)$
At $25^{o} C$ , $E_{c e l l}^{o} = 0.47 v o l t, R = 8.314 J K^{- 1} {m o l}^{- 1}, F = 96500 c o u l o m b$

Open in App

Solution

Let us apply Nernst equation at equilibrium
$E_{c e l l}^{o} = \frac{0.0591}{n} log K_{c}$
$0.47 = \frac{0.0591}{n} log K_{c}$
$K_{c} = a n t i log \frac{0.47 \times 2}{0.0591}$
$= 8.5 \times 10^{15}$

Suggest Corrections

Similar questions

25^{o} C

C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)

E_{c e l l}^{o} = 0.47 V, R = 8.134 J K^{- 1} F = 96500 C

Calculate the equilibrium constant of the reaction.
$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$ , $E_{c e l l}^{⊖} = 0.46 V$

C u (s) + 2 A g^{+} (a q) ⇋ C u^{2 +} (a q) + 2 A g (s),

C u (s) + 2 {A g}^{+} (a q) ⟶ {C u}^{2 +} (a q) + 2 A g (s)

E^{o} = 0.46 V

298 K

C u (s) + 2 A g^{+} (a q) ⇌ C u^{2 +} (a q) + 2 A g (s)

E^{\circ} = 0.46 V

298 K

Join BYJU'S Learning Program