calculate the equilibrium constant for the reaction at 25^°C Cu(s) + 2Ag+(aq)=Cu2+(aq) + 2Ag (s) Given E^°cell =-0.46 V.

Open in App

Solution

Suggest Corrections

Similar questions

Calculate the equilibrium constant of the reaction.
$C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)$ , $E_{c e l l}^{⊖} = 0.46 V$

K_{c}

C u (s) + 2 A g^{+} (a q .) ⇌ C u^{2 +} (a q .) + 2 A g (s) (E_{c e l l}^{\circ} = 0.46 V)

C u (s) + 2 A g^{+} (a q) ⇌ C u^{2 +} (a q) + 2 A g (s)

E^{\circ} = 0.46 V

298 K

25^{o} C

C u (s) + 2 A g^{+} (a q) \to C u^{2 +} (a q) + 2 A g (s)

E_{c e l l}^{o} = 0.47 V, R = 8.134 J K^{- 1} F = 96500 C

C u (s) + 2 A g^{+} (a q) ⇋ C u^{2 +} (a q) + 2 A g (s),

Join BYJU'S Learning Program