Calculate the equilibrium constant for the reaction at 25- C- Fe - CuSO 4- FeSO 4- CuGiven EO Pi z0-0-44 V - EO PLu0-0-337 VA- 10-26-33B- 10-20-69C- 10-20-69D- 10-26-33

The correct option is D 10 –26.33 ...

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Reaction Quotient

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Question

Calculate the equilibrium constant for the reaction at 25 ºC.

10 +26.33

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10 --20.69

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10 --26.33

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10 +20.69

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F e + C u S O_{4} ⟶ F e S O_{4} + C u

25^{o}

E_{(F e / F e^{2 +})}^{0} = 0.44 V

E_{(C u / C u^{2 +})}^{0} = - 0.337 V

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{0}

E^{0} (F e / F e^{2 +}) = 0.44 V, E^{0} (C u / C u^{2 +}) = - 0.337 V

F e + {C u S O}_{4} ⇌ {F e S O}_{4} + C u

E_{F e / F e}^{o} = 0.44 V; E_{C u / {C u}^{2 +}}^{o} = - 0.337 V

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{o} C

E^{0} [F e \to F e^{2 +}) = 0.44 V

E^{0} (C u \to C u^{2 +}) = - 0.337 V

F e + C u S O_{4} ⇌ F e S O_{4} + C u

25^{0}

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