Calculate the equilibrium constant for the reaction $F e + C u S O_{4} ⇌ F e S O_{4} + C u$ at $25^{0}$ C. Given $E^{0} (F e / F e^{2 +}) = 0.44 V, E^{0} (C u / C u^{2 +}) = - 0.337 V$ .

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Solution

$E_{c e l l}^{o} = E_{c a t h o d e} - E_{a n o d e}$
$= 0.44 - (- 0.337)$
$= 0.44 + 0.337$
$= 0.777$
At equilibrium $E_{c e l l} = 0$
So, $E_{c e l l}^{o} = 0.059 / n log K_{C}$
$\Rightarrow 0.777 = \frac{- 0.059}{2} log K_{C}$
$\Rightarrow log K_{C} = \frac{1.55}{- 0.059}$ .

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F e + C u S O_{4} ⟶ F e S O_{4} + C u

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E_{(C u / C u^{2 +})}^{0} = - 0.337 V

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