The equivalent weight of KI should be 332 g, ie, the double of its mol. weight : 166g.
As it's n-factor is 0.5, the equi. weight is = Mol. Weight/n-factor.
First balance the equation:
2 CuSO4 + 4 KI→Cu2I2 + 2 K2SO4 + I2
Now the O.S. of I in KI is -1, in I2 is 0 & Cu2I2 it is -1.
So for every 4 molecules of I, there is only a change of 1 oxidation state in 2 molecules of I.
So, n-factor of KI = 2/4 = 0.5
REGARDS,
CHEMISTRY EXPERT