Question

Calculate the equivalent weight of potassium dichromate with step by step explanation

Answer 1

Dear Student,

Potassium dichromate i.e K₂Cr₂O₇ is a good oxidising agent and hence reduces itself efficiently. Here, the Cr in +6 oxidation state is reduced to +3 oxidation state. Since, there is an involvement of 3 electrons per Cr-atom, or 6 electrons per mole of ​K₂Cr₂O₇ the equivalent weight of ​K₂Cr₂O₇ is:

$Eq.Wt.=\frac{Molecularweight}{6}=\frac{294.18}{6}=49.03gmo{l}^{-1}$

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