Calculate the escape velocity from the moon- The mass of the moon is 7-4-1022kg and the radius of the moon is 1740 km

The escape velocity is given by v=√(2GMR) v=√(2× 6.67× 10^ 11× 7.4× 10^221740× 10^3) ∴ v=2382 m/s≈2.4 km/s ...

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Standard XII

Physics

Velocity of Separation and Approach

Calculate the...

Question

Calculate the escape velocity from the moon. The mass of the moon is $7.4 \times 10^{22} kg$ and the radius of the moon is $1740 km$

1.4 km/hr

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2.4 km/s

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1.4 km/s

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2.4 km/hr

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Solution

The correct option is B $2.4 km/s$
The escape velocity is given by
$v = \sqrt{\frac{2 G M}{R}}$
$v = \sqrt{\frac{2 \times 6.67 \times 10^{- 11} \times 7.4 \times 10^{22}}{1740 \times 10^{3}}}$
$∴ v = 2382 m/s \approx 2.4 km/s$

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Calculate the escape velocity from the moon. The mass of the moon is 7.4×1022kg and the radius of the moon is 1740 km

The correct option is B 2.4 km/sThe escape velocity is given by v=√2GMR v=√2×6.67×10−11×7.4×10221740×103 ∴v=2382 m/s≈2.4 km/s

Calculate the escape velocity from the moon. The mass of the moon is $7.4 \times 10^{22} kg$ and the radius of the moon is $1740 km$

The correct option is B $2.4 km/s$
The escape velocity is given by
$v = \sqrt{\frac{2 G M}{R}}$
$v = \sqrt{\frac{2 \times 6.67 \times 10^{- 11} \times 7.4 \times 10^{22}}{1740 \times 10^{3}}}$
$∴ v = 2382 m/s \approx 2.4 km/s$