Calculate the escape velocity of a body from the surface of the earth.
[Given: $G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}, R = 6400 k m, g = 9.8 m . s^{2}]$

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Solution

Formula,

$v_{e} = \sqrt{\frac{2 G M}{R}}$

$= \sqrt{\frac{2 \times 6.67 \times 10^{- 11} \times 6 \times 10^{24}}{6400}}$

$∴ v_{e} = 11.2 k m$

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G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}, M = 6 \times 10^{24} k g, R = 6400 k m

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G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}

R = 6400 k m, M = 6 \times 10^{24} k g

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R = 6400 k m

M = 6 \times 10^{24} k g

G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}

[G i v e n G = 6.67 \times 10^{- 11} N m^{2} / k g^{2}, M = 6 \times 10^{24} k g, R = 6400 k m]

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