Question

Calculate the escape velocity on the surface of moon.If radius of moon is 1740 km and mass $7.4\times {10}^{22}$ kg.

Answer 1

Escape velocity is given by;

$v_e=\sqrt{2gR}$ where g is gravitational acceleration and R is radius

$v_e=\sqrt{\frac{2GMR}{R^2}}=\sqrt{\frac{2GM}{R}}$

$=\sqrt{\frac{2\times 6.67\times {10}^{-11}\times 7.4\times {10}^{22}}{1740\times {10}^3}}$

$=2381m/s$