wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the extent of hydrolysis of 0.005 MK2CrO4[K2=3.1×107 for H2CrO4].

Open in App
Solution

K2CrO4 added in to water.
CrO24+H2OHCrO4+OH
Kb=Kb=KwK2=(HCrO4)(OH)CrO24
By substituting the K2 & Kw & concentration. We will get 0.25% is the estent of hydrolysis.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hydrolysis
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon