Calculate the final molarity when 2.0 litre of 3.0 M sugar solution and 3.0 litre of 2.5 M sugar solution are mixed and then diluted to 10 litres with water.

2.35 M

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1.35 M

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1.55 M

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3.35 M

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Solution

The correct option is B $1.35 M$
Total moles = $m o l a r i t y \times v o l u m e$

= $2 \times 3 + 3 \times 2.5$ = $13.5 m o l e s$

Total volume = $10 L$

Molarity= $\frac{m o l e s}{v o l u m e} = \frac{13.5}{10}$ = $1.35 M$

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