Calculate the final volume of a gas, if the original pressure of the gas at S.T.P. is doubled and its temperature is made three times.

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Solution

According to the ideal gas law $P V = n R T$ and at $S T P$ , $\frac{P V}{T} = \frac{P_{1} V_{1}}{T_{1}}$
$\Rightarrow$ if $P_{1} = 2 P, T_{1} = 3 T,$ then $V_{1} = \frac{P V \times 3 T}{T \times 2 P} = \frac{3}{2} V = 1 \frac{1}{2} V$

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Calculate the final volume of a gas, if the original pressure of the gas at S.T.P. is doubled and its temperature is made three times.

According to the ideal gas law PV=nRT and at STP, PVT=P1V1T1 ⇒ if P1=2P,T1=3T, then V1=PV×3TT×2P=32V=112V

According to the ideal gas law $P V = n R T$ and at $S T P$ , $\frac{P V}{T} = \frac{P_{1} V_{1}}{T_{1}}$
$\Rightarrow$ if $P_{1} = 2 P, T_{1} = 3 T,$ then $V_{1} = \frac{P V \times 3 T}{T \times 2 P} = \frac{3}{2} V = 1 \frac{1}{2} V$