Suppose the volume at STP to be V and pressure to be P and temperature to be T
Now, the number of moles of the gas X present
n=PVRT
PV=nRT
Now, the second condition
P2=2P
T2=3T
Now, the volume
V2=nRT2P2
Now, substituting the value of T2 and P2
V2=nRT2P2
V2=PVT×3T2P
V2=32V
V2=1.5V
So, the final volume will be 1.5 fold the original volume.