Question

Calculate the following expression $2021x^{2022}+5$ for $x=0.$

Answer 1

$\underset{–}{\text{Need to Calculate:}}$ $2021x^{2022}+5$ for $x=0$
By substituting $x=0$ in the expression $2021x^{2022}+5,$ we get:

$2021\times 0^{2022}+5$
$=2021\times 0+5$ $[\because 0^a=0,\forall a\in R]$
$=0+5$ $[\because 0\times \text{anything defined}=0]$
$=5$

Therefore, the value of $2021x^{2022}+5$ for $x=0$ is $5.$