Question

Calculate the following limits.
$\underset{n\to \infty }{lim}\frac{n^2}{1-9n^2},nϵN.$

Answer 1

$\underset{n\to \infty }{lim}\frac{n^2}{1-9n^2}$

$=\underset{n\to \infty }{lim}\frac{1}{\frac{1}{n^2}-9}$

$=\frac{1}{\frac{1}{\infty }-9}$

$=-9$