Calculate the following, present in 16 g of $O_{2}$ .
(a) The number of moles (b) Number of molecules
(c) Number of gram atoms(d) Number of atoms
(e) volume occupied by it at S.T.P.(f) Number of protons.

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Solution

Molecular weight of oxygen is 32.
Thus the number of moles present in 16 g of $O_{2}$ will be 0.5
Number of molecules present will be $0.5 N_{A}$
Number of gram atoms will be $0.5 \times 2 N_{A} = N_{A}$ ( Since one molecule of oxygen contains 2 atoms of oxygen)
1 mol of a gas occupies $22.4 l$ at STP, thus given sample will occupy $11.2 l$ at STP.
No. of protons $= N o . o f g r a m a t o m s \times 8 = 8 N_{A}$ (Since one oxygen atom contains 8 protons)

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Calculate the following, present in 16 g of O2.(a) The number of moles (b) Number of molecules(c) Number of gram atoms(d) Number of atoms(e) volume occupied by it at S.T.P.(f) Number of protons.

Calculate the following, present in 16 g of $O_{2}$ .
(a) The number of moles (b) Number of molecules
(c) Number of gram atoms(d) Number of atoms
(e) volume occupied by it at S.T.P.(f) Number of protons.