Question

Calculate the force acting on a wire of length 1 m through which a current of 0.2 flows and the wire is placed perpendicular to the direction of magnetic field of strength 0.4T.

Answer 1

Dear Student,

Force= ILB sin$\theta$
I=current=0.2A
B=magnetic field=0.4T
L=length =1m

Force=0.2$\times$1$\times$0.4 sin(90)
(sin90=1)
Force=0.08N

Thank You!