Question

Calculate the force between the two point masses of 25 kg and 50 kg which are seperated by a distance of 10 m.

• A. $0.833$ $\times$ ${10}^{-9}$ $N$
• B. $6.67$ $\times$ ${10}^{-10}$ $N$
• C. $2.27$ $\times$ ${10}^{-11}$ $N$
• D. $3.34$ $\times$ ${10}^{-9}$ $N$

Answer 1

The correct option is A $0.833$ $\times$ ${10}^{-9}$ $N$

Given:
First mass, $m_1=25kg$
Second mass, $m_2=50kg$
Distance between the masses, $r=10m$

According to Universal law of gravitation, the force of attraction between two bodies is:
$F=\frac{G{m}_1{m}_2}{r^2}$
$F=\frac{6.67\times {10}^{-11}\times 25\times 50}{{10}^2}$
$F=0.833\times {10}^{-9}N$