Calculate the force between two masses of 100 kg and 1000 kg separated by a distance of 10 m ( $G = 6.67 \times 10^{- 11}$ N $\frac{m^{2}}{k g^{2}}$ ).

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Solution

According to Newton's law of gravitation, force of attraction between two bodies is

$F = \frac{G m_{1} m_{2}}{r^{2}}$

Here, $m_{1}$ = 100 kg; $m_{2}$ = 1000 kg; r = 10 m; $G = 6.67 * 10^{- 11}$ N $\frac{m^{2}}{k g^{2}}$

$F = \frac{6.67 \times 10^{- 11} \times 100 \times 1000}{10^{2}}$

= $6.67 \times 10^{- 8}$ N

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