Calculate the force component in the direction of displacement.

200 N

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100 N

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50 N

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150 N

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Solution

The correct option is B 100 N
Force F = 200 N.
Angle of the inclined plane, $θ = 60^{\circ}$
Displacement was along the inclined plane.

So the component of force along the inclined plane = F cos $θ$
$= 200 \times c o s (60)$
$= 200 \times \frac{1}{2}$
= 100 N

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Calculate the force component in the direction of displacement.

The correct option is B 100 NForce F = 200 N. Angle of the inclined plane, θ=60∘ Displacement was along the inclined plane. So the component of force along the inclined plane = F cosθ =200×cos(60) =200×12 = 100 N

The correct option is B 100 N
Force F = 200 N.
Angle of the inclined plane, $θ = 60^{\circ}$
Displacement was along the inclined plane.

So the component of force along the inclined plane = F cos $θ$
$= 200 \times c o s (60)$
$= 200 \times \frac{1}{2}$
= 100 N