Question

Calculate the force experienced by a conductor of length $0.3m$ carrying a current of $1A$, when placed in a uniform magnetic field of intensity $1.2N/A^2$.

Answer 1

Step 1. Given data

Length of the conductor is, $L=0.3m$

Current is, $I=1A$

Intensity of the magnetic field is, $B=1.2N/A^2$.

Step 2. Formula used

Force on a straight current-carrying conductor placed in a uniform perpendicular magnetic field, $F=B\times L\times I$

Where, $B$ is the magnetic field, $L$ is the length, $I$ is the current.

Step 3. Finding magnetic force

$F=BlI$

By putting all the given values,

$F=1.2N/A^2\times 0.3m\times 1A$

After solving we get,

$F=0.36N$.

Therefore the magnetic force is $\mathbf{0}\mathbf{.}\mathbf{36}\mathbf{}\mathit{N}$.