Calculate the force needed to punch a 1.46cm diameter hole in a steel plate is 1.27cm thick. The ultimate shear strength of steel is 345N/m2

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Solution

stress = F/pir^2

345x10^6 = F/3.14x(2x10^-2)^2 -(0.73x10-22)^2

Therefore F = 345x10^6x3.14x(3.47x10^-4)

= 3759x10^2N

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Calculate the force needed to punch a 1.46cm diameter hole in a steel plate is 1.27cm thick. The ultimate shear strength of steel is 345N/m2

stress = F/pir^2 345x10^6 = F/3.14x(2x10^-2)^2 -(0.73x10-22)^2 Therefore F = 345x10^6x3.14x(3.47x10^-4) = 3759x10^2N

stress = F/pir^2

345x10^6 = F/3.14x(2x10^-2)^2 -(0.73x10-22)^2

Therefore F = 345x10^6x3.14x(3.47x10^-4)

= 3759x10^2N