Calculate the force of gravitation between two objects of masses 50 kg and 120 kg respectively kept at a distance of 10 m from one another. (Gravitational constant, G = 6.7 ✕ 10⁻¹¹ Nm² kg⁻²)

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Solution

F (gravitational force) = ?
G (gravitational constant) = 6.7 × 10⁻¹¹ Nm² kg⁻²
M (mass of body)= 120 kg
m (mass of body) = 50 kg
d (distance from each other) = 10 m
$F = \frac{GMm}{d^{2}} = \frac{6.7 \times 10^{- 11} \times 120 \times 50}{{(10)}^{2}} = \frac{6.7 \times 10^{- 11} \times 12 \times 5 \times 100}{100} = 6.7 \times 10$ ^-11×12×5 =402×10^-11N =4.02×10^-9N Answer: F=4.02×10^-9N

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Calculate the force of gravitation between two objects of masses 50 kg and 120 kg respectively kept at a distance of 10 m from one another. (Gravitational constant, G = 6.7 ✕ 10−11 Nm2 kg−2)

F (gravitational force) = ? G (gravitational constant) = 6.7 × 10−11 Nm2 kg−2 M (mass of body)= 120 kg m (mass of body) = 50 kg d (distance from each other) = 10 m F=GMmd2 =6.7×10-11×120×50102 =6.7×10-11×12×5×100100 =6.7×10-11×12×5 =402×10-11N =4.02×10-9N Answer: F=4.02×10-9N

Calculate the force of gravitation between two objects of masses 50 kg and 120 kg respectively kept at a distance of 10 m from one another. (Gravitational constant, G = 6.7 ✕ 10⁻¹¹ Nm² kg⁻²)