MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Overall Equilibrium

Calculate the...

Question

Calculate the force that produces a moment of force of 2100 dyne-cm, when the perpendicular distance between point of application of force and turning point is 60 cm.

Open in App

Solution

$T = F o r c e \times ⊥ d i s t a n c e$
$2100 = F o r c e \times 60 c m$
$F o r c e = \frac{2100}{60} = 35 d y n e$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Calculate the force that produces a moment of force of

2100 d y n e c m

, when the perpendicular distance between point of application of force and turning point is

60 c m

Q. A force of 1875 dyne acts on a rigid body, such that perpendicular distance between fulcrum and point of application of force is 20 cm. Calculate moment of force.

1600

dyne acts on a rigid body, such that the perpendicular distance between force and turning point is

40 c m

. Calculate the moment of force.

1875

dyne acts on a rigid body, such that perpendicular distance between fulcrum and point of application of force is

20 c m

. Calculate the moment of force.

525 N

produces a moment of force of

420 N m

. Calculate the shortest distance between the point of application of force and the turning point.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Equilibrium 2.0

PHYSICS

Watch in App

explore_more_icon

Explore more

Overall Equilibrium

Standard X Physics

Join BYJU'S Learning Program

CrossIcon