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Dipole Moment

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Question

Calculate the fractional charge value of HCl the dipole moment is $1.02$ D.

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Solution

The magnitude of dipole moment formed by two equal and opposite fractional charges $+ Q$ and $- Q$ separated by a length $l$ is given from $M = Q l$
$\Rightarrow Q = \frac{M}{l}$
$\Rightarrow 1.020 0.127 n m = \frac{1.02 \times 3.33564 \times 10^{- 30} m}{0.127 \times 10 m}$
$= 2.679 \times 10^{- 20}$ coulombs.
Fractional charge value= $0.167 e V$

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