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Byju's Answer
Standard XII
Chemistry
Elevation in Boiling Point
Calculate the...
Question
Calculate the free energy change for the dissociation of potassium nitrate in water at 298K. (given: delta H = 34 KJ/mol, delta S = 0.116KJ/K/mol)
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Solution
Free energy =G = H - (TS)
=G=34x10³-(298x0.116x10³)
G=34000-(34568)
G=568joule
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2
Similar questions
Q.
The Born Haber cycle below represents the energy changes occurring at 298K when
K
H
is formed from its elements
v :
Δ
H
a
t
o
m
i
s
a
t
i
o
n
K
=
90
k
J
/
m
o
l
w :
Δ
H
i
o
n
i
s
a
t
i
o
n
K
=
418
k
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m
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x :
Δ
H
d
i
s
s
o
c
i
a
t
i
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n
H
=
436
k
J
/
m
o
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y :
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H
e
l
e
c
t
r
o
n
a
f
f
i
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i
t
y
H
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k
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m
o
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z :
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a
t
t
i
c
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K
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Calculate the value of
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Q.
The Gibbs free energy change for the reaction for which
Δ
H
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−
393.4
k
J
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Δ
S
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−
2.9
J
K
−
1
m
o
l
−
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at 298K is:
Q.
The Born Haber cycle below represents the energy changes occurring at 298K when
K
H
is formed from its elements
v :
Δ
H
a
t
o
m
i
s
a
t
i
o
n
K
=
90
k
J
/
m
o
l
w :
Δ
H
i
o
n
i
s
a
t
i
o
n
K
=
418
k
J
/
m
o
l
x :
Δ
H
d
i
s
s
o
c
i
a
t
i
o
n
H
=
436
k
J
/
m
o
l
y :
Δ
H
e
l
e
c
t
r
o
n
a
f
f
i
n
i
t
y
H
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78
k
J
/
m
o
l
z :
Δ
H
l
a
t
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i
c
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K
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On complete reaction with water,
0.1
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l
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Q.
The Born Haber cycle below represents the energy changes occurring at 298K when
K
H
is formed from its elements
v :
Δ
H
a
t
o
m
i
s
a
t
i
o
n
K
=
90
k
J
/
m
o
l
w :
Δ
H
i
o
n
i
s
a
t
i
o
n
K
=
418
k
J
/
m
o
l
x :
Δ
H
d
i
s
s
o
c
i
a
t
i
o
n
H
=
436
k
J
/
m
o
l
y :
Δ
H
e
l
e
c
t
r
o
n
a
f
f
i
n
i
t
y
H
=
78
k
J
/
m
o
l
z :
Δ
H
l
a
t
t
i
c
e
K
H
=
710
k
J
/
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o
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Out of v to y the most endothermic is___.
Q.
Calculate the dissociation constant of
N
H
4
O
H
at 298 K, if
△
H
⊝
and
Δ
S
⊝
for the given changes are as follows:
N
H
3
+
H
⊕
⇌
⊕
N
H
4
;
Δ
H
⊝
=
−
52.2
k
J
m
o
l
−
1
,
Δ
S
⊝
=
1.67
J
K
−
1
m
o
l
−
1
H
2
O
⇌
H
⊕
+
⊝
O
H
;
Δ
H
⊝
=
56.6
k
J
m
o
l
−
1
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Δ
S
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J
K
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m
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