Calculate the freezing of an aqueous solution containing 10.50g of mgbr2in 200g of water

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Solution

Given,

w2=10.50g
w1=200g

Molar mass of MgBr2;
M2=184g

using the formula,

dTf= (1000×Kf×w2)/(w1×M2)

=(1000×1.86×10.50)/(200×184)
=0.53

now,
Tf=To-dTf
=273-0.53
=272.47K

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Calculate the freezing point of an aqueous solution containing 10.50 g of MgBr₂ in 200 g of water (Molar mass of MgBr₂ is 184 g) (K_f for water is 1.86 K kg /mol)

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Calculate the freezing of an aqueous solution containing 10.50g of mgbr2in 200g of water

Given, w2=10.50g w1=200g Molar mass of MgBr2; M2=184g using the formula, dTf= (1000×Kf×w2)/(w1×M2) =(1000×1.86×10.50)/(200×184) =0.53 now, Tf=To-dTf =273-0.53 =272.47K

Given,

w2=10.50g
w1=200g

Molar mass of MgBr2;
M2=184g

using the formula,

dTf= (1000×Kf×w2)/(w1×M2)

=(1000×1.86×10.50)/(200×184)
=0.53

now,
Tf=To-dTf
=273-0.53
=272.47K