Calculate the frequency data of age of class students.

Open in App

Solution

Age (x)

No. of students(f)

$(x \times f)$

10

4

40

12

15

180

14

24

336

15

30

450

13

12

156

11

9

99

9

11

99

Total =105

Total=1360

$M e a n = \frac{\sum f . x}{\sum f}$

$= \frac{1360}{105}$

$= 12.95 \sim 13$

Suggest Corrections

Similar questions

Q. The following data give the number of boys of a particular age in a class of 40 students.

Age (in years)	15	16	17	18	19	20
Frequency (f_i)	3	8	9	11	6	3

Calculate the mean age of the students.

Q. The following data give the number of boys of a particular age in a class of 40 students. Calculate the mean age of the students by assumed mean method.
Age (in years) Number of students

13	3
14	8
15	9
16	11
17	6
18	3

The age of 15 students in a class is given below:

10, 11, 12, 10, 10, 12, 13, 13, 11, 10, 12, 11, 12, 13, 10

Find the frequency of age 13.

The following data give the number of boys of a particular age in a class of 40 students.
$\begin{matrix} Age (in years) & 15 & 16 & 17 & 18 & 19 & 20 Frequency (f_{i}) & 3 & 8 & 9 & 11 & 6 & 3 \end{matrix}$
Calculate the mean ager of the students.

Q. Calculate the average age of students in a class using Assumed mean method.

Join BYJU'S Learning Program

Age (x)	No. of students(f)	$(x \times f)$
10	4	40
12	15	180
14	24	336
15	30	450
13	12	156
11	9	99
9	11	99
	Total =105	Total=1360

Calculate the frequency data of age of class students.

Age (x) No. of students(f) (x×f) 10 4 40 12 15 180 14 24 336 15 30 450 13 12 156 11 9 99 9 11 99 Total =105 Total=1360 Mean=∑f.x∑f=1360105=12.95∼13

Age (x)

No. of students(f)

$(x \times f)$

10

4

40

12

15

180

14

24

336

15

30

450

13

12

156

11

9

99

9

11

99

Total =105

Total=1360

$M e a n = \frac{\sum f . x}{\sum f}$

$= \frac{1360}{105}$

$= 12.95 \sim 13$