Calculate the frequency,in hertz, for the following cyclical events.
Ten swings of a pendulum in 6.7 s.

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Solution

Step 1: Given data.
No.of oscillations= 10 .
Time = 6.7 seconds.
Step 2: Formulas Required.
Frequency is number of oscillations per unit time .
Frequency (f)= $\frac{n o . o f o s c i l l a t i o n s}{t i m e}$ .
Step 3: Calculation.
Here total numbers of oscillations =10.
Total time =6.7 seconds .
Frequency (f)= $\frac{n o . o f o s c i l l a t i o n s}{t i m e}$ .
f = $\frac{10 o s c i l l a t i o n s}{6.7 s e c o n d s}$ .
f= $1.492 H e r t z$ .
Step 4: conclusion.
Hence,the frequency for 10 oscillations in 6.7 seconds in a cyclic event is $1.492 H e r t z$ .

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