Question

Calculate the frequency of light emitted for an electron transition from the sixth to second orbit of the hydrogen atom. In what region of the spectrum does this light occur?

Answer 1

The formulae to find the frequency of light:

$\frac{1}{\lambda }=R[\frac{1}{n_1^2}-\frac{1}{n_2^2}]n_1=2,n_2=6,R=109677c{m}^{-1}\frac{1}{\lambda }=109677[\frac{1}{4}-\frac{1}{36}]=109677\times 6.2222=2437c{m}^{-1}v=\frac{c}{\lambda }=3\times {10}^{10}\times 243707.31\times {10}^{14}{sec}^{-1}$