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Question

Calculate the frequency of the spectral line corresponding to the transition of an electron from n1=2 and n2=4 in a hydrogen atom.

A
6.172×1014 s1
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B
3.086×106 s1
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C
6.172×106 s1
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D
3.086×1014 s1
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Solution

The correct option is A 6.172×1014 s1
¯v=R(1n211n22)n1=2n2=4¯v=1λ
R = Rydberg constant = 109678 cm1
Substituting the values in the equation,
¯v=R(1n211n22)cm11λ=20,564.625 cm1λ=4.86×105 cmλ=4.86×107 mfrequency(v)=cλv=3×108 ms14.86×107 m=6.172×1014 s1

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