wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the fundamental frequency of a string stretched by a 1 kg weight if the length of the string is 0.4 m. Given that 5 m length of the wire weight 2 g. (Assume tension to be constant in the string and equal to the point attached to the weight)

A
125210 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
125410 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12510 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 125210 Hz
Tension, T=mg=1×10=10 N
Mass per unit length of the rope, μ=0.0025=12500 kg/m
Wave velocity, v=Tμ=5010 m/s
Fundamental frequency, f0=v2l=50102×0.4=125210 Hz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Normal Modes on a String
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon