Calculate the gram molecular mass of $N_{2}$ , if $360 c m^{3}$ at STP weighs 0.45 g.

14 g

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28 g

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56 g

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21 g

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Solution

The correct option is B
28 g

The mass of 22.4L of a gas at STP is equal to its gram molecular mass.

$360 c m^{3} o f N_{2}$ at STP weighs 0.45g

Therefore, $22400 c m^{3} o f N_{2}$ will weigh = $\frac{0.45}{360} \times 22400$ = 28 g

Gram molecular mass of $N_{2}$ = 28 g

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Similar questions

Calculate the relative molecular mass of $C O_{2}$ if 300 ml of gas at STP weighs 0.30 g. Given 1 litre of $H_{2}$ at STP weighs 0.09 g.

Calculate:

a) the gram molecular mass of chlorine if 308 cm cube of it at STP weighs 0.979 grams

B) the volume of 4 gram of H2 at 4 atmospheres.

C) the mass of oxygen in 2.2 litres of carbon dioxide at STP

3.011 \times 10^{23}

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