Calculate the H.C.F of $24 x y, 12 x^{2}, 10 y^{2} z$ .

2 (x y)

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2

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2 x^{2} y z

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2 y^{2} z

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Solution

The correct option is C $2$
Factors :-
$24 x y$ = $2 \times 2 \times 2 \times 3 \times x \times y$
$12 x^{2}$ = $2 \times 2 \times 3 \times x \times x$
$10 y^{z}$ = $2 \times 5 \times y \times y$
H.C.F = $2$

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