Calculate the half-life of a first order reaction in seconds with a rate constant of $0.398 / m i n$ .

0.0276 s e c

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1.74 s e c

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0.029 s e c

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104 s e c

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Solution

The correct option is D $104 s e c$
Since we know half-life of first order reaction is given by, $t_{1 / 2} = \frac{0.693}{k}$

Given $k = \frac{0.398}{m i n}$

$⟹ t_{1 / 2} = \frac{0.693 \times 60}{0.398} = 104.4 s e c$

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