Question

Calculate the heat absorbed by a system in going through the cyclic process shown in figure.

Answer 1

Heat absorbed = Work done

= Area under the graph in the given case.

Heat absorbed = area of the circle

$=\pi \times {10}^4\times {10}^{-6}\times {10}^3\text{J}$

$=3.14\times 10=31.4\text{J}$