Question

Calculate the heat absorbed by the system in going through the process shown in the given figure

• A. $31.4J$
• B. $3.14J$
• C. $3.14\times {10}^{4}J$
• D. none

Answer 1

The correct option is A $31.4J$

As it is a cyclic process there is no change in internal energy and thus work done is equal to heat absorbed. Work done is area enclosed under the $PV$ graph. Thus we get
Work done = Heat absorbed = $\pi r^2=\pi \left(P_r\right)\left(V_r\right)$
$=3.14(100\times {10}^3)(100\times {10}^{-6})$
$=31.4J$