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Question

Calculate the heat change during the reaction 24g C and 128g S following :the change C+S2CS2; ΔH=22K cal.

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Solution

C+S2CS2ΔH=22kcal
1 mole of C=12g
1 mole of S2=64g
Therefore,
24g of C=2 moles
128g of S2=2 moles
Given that heat change during the reaction of 12g of C and 64g of S is 22kcal
Therefore
2×[C+S2CS2ΔH=22kcal]
2C+2S22CS2ΔH=44kcal
Hence the heat change during the reaction 24g of C and 128g of S is 44kcal.

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