Calculate the heat energy liberated by 45 g of steam so as to form water at 100 °C (specific latent heat of vaporization of water is 2260 J/g.

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Solution

Step 1: Given Data
Mass of steam = 45 g.
Specific latent heat of vaporization = 2260 J/g.
Step 2: Formula used
$Q = m a s s x l a t e n t e n e r g y$
Step 3: Calculation of Heat energy
$Q = m a s s x l a t e n t e n e r g y$
$Q = 45 x 2260$
$Q = 101700 J$
Hence, the heat energy required is $101700 J$ .

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