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Question
Calculate the heat involved in a reaction for the isothermal expansion of one mole of a ideal gas at 27o C from a volume of 50 L to 100 L.
Calculate the heat involved in a reaction for the isothermal expansion of one mole of a ideal gas at 27o C from a volume of 50 L to 100 L.
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Solution
The correct option is C Q = 1729 J
Since the process is isothermal.
ΔU=0
W = −2.303nRT logV2V1
where V2 and V1 is the final and initial volume respectively.
n = moles of ideal gas
W = −2.303×8.314×300 log10050
W = −1729J
From the first law,
ΔU=Q+W
Q=−W = 1729 J
Since the process is isothermal.
ΔU=0
W = −2.303nRT logV2V1
where V2 and V1 is the final and initial volume respectively.
n = moles of ideal gas
W = −2.303×8.314×300 log10050
W = −1729J
From the first law,
ΔU=Q+W
Q=−W = 1729 J
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