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Byju's Answer
Standard XII
Chemistry
Enthalpy of Combustion
Calculate the...
Question
Calculate the heat of combustion of benzene from the following data:
a.
6
C
(
s
)
+
3
H
2
(
g
)
⟶
C
6
H
6
(
l
)
,
Δ
H
=
49.0
k
J
b.
H
2
(
g
)
+
1
/
2
O
2
(
g
)
⟶
H
2
O
(
l
)
,
Δ
H
=
−
285.8
k
J
c.
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
,
Δ
H
=
−
389.3
k
J
A
Δ
c
H
=
−
3242.2
k
J
m
o
l
−
1
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B
Δ
c
H
=
+
3242.2
k
J
m
o
l
−
1
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C
Δ
c
H
=
−
4242.2
k
J
m
o
l
−
1
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D
None of these
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Solution
The correct option is
C
Δ
c
H
=
−
3242.2
k
J
m
o
l
−
1
As given,
a.
6
C
(
s
)
+
3
H
2
(
g
)
⟶
C
6
H
6
(
l
)
,
Δ
H
1
=
49.0
k
J
b.
H
2
(
g
)
+
1
/
2
O
2
(
g
)
⟶
H
2
O
(
l
)
,
Δ
H
2
=
−
285.8
k
J
c.
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
,
Δ
H
3
=
−
389.3
k
J
C
6
H
6
(
l
)
+
15
2
O
2
(
g
)
⟶
6
C
O
2
(
g
)
+
3
H
2
O
(
l
)
Δ
H
=
?
Δ
H
=
3
Δ
H
2
+
6
Δ
H
3
−
Δ
H
1
=
3
×
(
−
285.8
)
+
6
×
(
−
389.3
)
−
49.0
=
−
857.4
−
2335.8
−
49
=
−
3242.2
k
J
m
o
l
−
1
Suggest Corrections
0
Similar questions
Q.
The enthalpy of combustion of benzene from the following data will be:
(i)
6
C
(
s
)
+
3
H
2
(
g
)
→
C
6
H
6
(
l
)
;
Δ
H
=
+
45.9
k
J
(ii)
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
l
)
;
Δ
H
=
−
285.9
k
J
(iii)
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
393.5
k
J
Q.
Calculate the heat of formation of acetic acid from the following data:
a.
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
,
Δ
H
=
−
393.7
k
J
b.
H
2
(
g
)
+
1
/
2
O
2
(
g
)
⟶
H
2
O
(
l
)
,
Δ
H
=
−
285.8
k
J
c.
C
H
3
C
O
O
H
(
l
)
+
2
O
2
(
g
)
⟶
2
C
O
2
(
g
)
+
2
H
2
O
(
l
)
,
Δ
H
=
−
873.2
k
J
Q.
From the following data of heats of combustion, find the heat of formation of
C
H
3
O
H
(
l
)
:
C
H
3
O
H
(
l
)
+
3
2
O
2
(
g
)
⟶
C
O
2
(
g
)
+
2
H
2
O
(
l
)
;
Δ
H
=
−
726
k
J
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
;
Δ
H
=
−
394
k
J
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
l
)
;
Δ
H
=
−
286
k
J
Q.
From the following data of heats of combustion, find the heat of formation of
C
H
3
O
H
(
l
)
C
H
3
O
H
(
l
)
+
3
2
O
2
(
g
)
→
C
O
2
(
g
)
+
2
H
2
O
(
l
)
;
△
r
H
⊖
=
−
726
k
J
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
,
Δ
H
=
−
394
k
J
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
l
)
,
Δ
H
=
−
286
k
J
Q.
Calculate the heat of formation of
C
H
3
C
O
O
H
(
l
)
at
25
∘
C
from the following data;
C
H
3
C
O
O
H
(
l
)
+
2
O
2
(
g
)
→
2
C
O
2
+
2
H
2
O
(
l
)
;
Δ
H
=
−
208.34
kcal
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
94.05
kcal
H
2
(
g
)
+
1
2
O
2
→
H
2
O
(
l
)
;
Δ
H
=
−
68.32
kcal
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