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Question

Calculate the heat of combustion of benzene from the following data:


a. 6C(s)+3H2(g)C6H6(l),ΔH=49.0kJ

b. H2(g)+1/2O2(g)H2O(l),ΔH=285.8kJ

c. C(s)+O2(g)CO2(g),ΔH=389.3kJ

A
ΔcH=3242.2kJmol1
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B
ΔcH=+3242.2kJmol1
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C
ΔcH=4242.2kJmol1
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D
None of these
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Solution

The correct option is C ΔcH=3242.2kJmol1
As given,
a. 6C(s)+3H2(g)C6H6(l),ΔH1=49.0kJ

b. H2(g)+1/2O2(g)H2O(l),ΔH2=285.8kJ

c. C(s)+O2(g)CO2(g),ΔH3=389.3kJ

C6H6(l)+152O2(g)6CO2(g)+3H2O(l)ΔH=?

ΔH=3ΔH2+6ΔH3ΔH1

=3×(285.8)+6×(389.3)49.0

=857.42335.849

=3242.2kJmol1

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