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Question

Calculate the heat of combustion of ethene
CH2=CH2(g)+3O2(g)2CO2(g)+2H2O(I)
The bond energy data are given below
C=C=619kJmol1
CH=414kJmol1
O=O=499kJmol1
C=O=724kJmol1
OH=460kJmol1

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Solution

Heat of combustion=Σ[bond energy of reactants]Σ[bond energy of products]
ΔHc=[(3×499)+619+(4×414)][(2×2×724)+(2×2×460)] kJ mol1
ΔHc=[1497+619+1656][2896+1840] kJ mol1
ΔHc=37724736 kJ mol1
ΔHc=964 kJ mol1

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