Calculate the heat of formation of acetic acid from the following data-CH 3 COOH l -2 O 2 g - 2 CO 2 g -2 H 2 O l - H -207-9 K calC s - O 2 g - CO 2 g - H -94-48 K calH 2 g -1-2 O 2 g - H 2 O l H -68-4 K calA- 117-86 K calB- -117-86 K calC- 116-86 K calD- -116-86 K cal

The correct option is B 117.86 K cal The required equation is 2C(s) + 2H_2(g) + O_2(g) → CH_3 COOH(l) H = ? CH_3COOH(l) + 2O_2(g) → 2CO_2(g) + 2H_ ...

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Byju's Answer

Standard XII

Chemistry

Heat of Formation

Calculate the...

Question

Calculate the heat of formation of acetic acid from the following data.

$C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l), △ H = - 207.9 K c a l$
$C (s) + O_{2} (g) \to C O 2 (g) △ H = - 94.48 K c a l$
$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) △ H = - 68.4 K c a l$

117.86 K cal

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116.86 K cal

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-116.86 K cal

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Solution

The correct option is B
-117.86 K cal

The required equation is $2 C (s) + 2 H_{2} (g) + O_{2} (g) \to C H_{3} C O O H (l) △ H = ?$
$C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l) △ H = - 207.9 K c a l - - - - - - (i)$
$C (s) + O_{2} (g) \to C O_{2} (g) △ H = - 94.48 K c a l - - - - - - (i i)$
$(g) H_{2} + \frac{1}{2} O_{2} (g) \to H_{2} O (l) △ H = - 68.4 K c a l - - - - - - (i i i)$
Multiply equation (ii) by 2 and also equation (iii) by 2, add both of subtracting equation (i) we get
$2 C + 2 O_{2} + 2 H_{2} + O_{2} - C H_{3} C O O H - 2 O_{2}$ $\to 2 C O_{2} + 2 H_{2} O - 2 C O_{2} - 2 H_{2} O$
$△ H C H_{3} C O O H = 2 (- 94.48) + 2 (- 68.4) - (- 207.9)$
$△ H C H_{3} C O O H = - 117.86 K c a l$

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Similar questions

Q. Calculate the heat of formation of acetic acid from the following data:
a.

C (s) + O_{2} (g) ⟶ C O_{2} (g)

Δ H = - 393.7 k J

H_{2} (g) + 1 / 2 O_{2} (g) ⟶ H_{2} O (l)

Δ H = - 285.8 k J

C H_{3} C O O H (l) + 2 O_{2} (g) ⟶ 2 C O_{2} (g) + 2 H_{2} O (l)

Δ H = - 873.2 k J

Q. Using the following thermochemical data

C (S) + O_{2} (g) \to C O_{2} (g)

Δ H = - 94.0 K c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l)

Δ H = - 68.0 K c a l

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l)

Δ H = - 210.0 K c a l

The heat of formation of acetic acid is

Q. Using the following thermochemical data,

C (s) + O_{2} (g) \to C O_{2} (g) Δ H = - 94.0 k c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) Δ H = - 68.0 k c a l

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l) Δ H = - 210.0 k c a l

the heat of formation of acetic acid is :

Q. Using the following thermochemical data,

C (s) + O_{2} (g) \to C O_{2} (g) Δ H = - 94.0 k c a l

H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) Δ H = - 68.0 k c a l

C H_{3} C O O H (l) + 2 O_{2} (g) \to 2 C O_{2} (g) + 2 H_{2} O (l) Δ H = - 210.0 k c a l

the heat of formation of acetic acaid is :

Heat of formation of $C H_{4}$ is:

If given:

$C (s) + O_{2} (g) \to C O_{2} (g) △ H = - 394 k J$

$H_{2} (g) + \frac{1}{2} O_{2} (g) \to H_{2} O (l) △ H = - 284 k J$

$C H_{4} (g) + 2 O_{2} (g) \to C O_{2} (g) + 2 H_{2} O (l) △ H = - 892 k J$

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Calculate the heat of formation of acetic acid from the following data. CH3COOH(l) + 2O2(g) →2CO2(g) + 2H2O(l), △H= −207.9 K cal C(s) + O2(g)→CO2(g) △H = −94.48 K cal H2(g) + 12O2(g)→H2O(l) △ H = −68.4 K cal