wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the heat of formation of acetic acid from the following data.

CH3COOH(l) + 2O2(g) 2CO2(g) + 2H2O(l), H= 207.9 K cal
C(s) + O2(g)CO2(g) H = 94.48 K cal
H2(g) + 12O2(g)H2O(l) H = 68.4 K cal

A

117.86 K cal

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

-117.86 K cal

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

116.86 K cal

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

-116.86 K cal

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

-117.86 K cal


The required equation is 2C(s) + 2H2(g) + O2(g)CH3COOH(l) H = ?
CH3COOH(l) + 2O2(g)2CO2(g) + 2H2O(l) H = 207.9 K cal (i)
C(s) + O2(g)CO2(g) H = 94.48 K cal (ii)
(g)H2 + 12 O2(g)H2O(l) H = 68.4 K cal (iii)
Multiply equation (ii) by 2 and also equation (iii) by 2, add both of subtracting equation (i) we get
2C + 2O2 + 2H2 + O2CH3COOH2O22CO2 + 2H2O2CO22H2O
HCH3COOH = 2(94.48) + 2(68.4)(207.9)
HCH3COOH = 117.86 K cal

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon