Calculate the heat of formation of anhydrous Al2Cl2 from 2Als - 6HClaq - Al2Cl6aq - 3H2g- H - -239-76 kcal H2g - Cl2g - 2HClg- H - -44-0 kcal HClg - Aq - HClaq- H - -17-32 kcal Al2Cl6s - Aq - Al2Cl6aq- H - -153-69 kcal-

2Al( s ) + 3Cl _ 2 ( s ) ⟶ Al _ 2 Cl _ 6 ( s ) Δ H=? (i) #160; 2Al( s ) +6HCl( aq ) → Al _ 2 Cl _ 6 ( aq ) +3 H _ 2 ( or ) , Δ H _ 1 = 239.76k ...

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Molar and Specific Heat Capacity

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Question

Calculate the heat of formation of anhydrous $A l_{2} C l_{2}$ from
$2 A l (s) + 6 H C l (a q) \to A l_{2} C l_{6} (a q) + 3 H_{2} (g), △ H = - 239.76 k c a l$
$H_{2} (g) + C l_{2} (g) \to 2 H C l (g), △ H = - 44.0 k c a l$
$H C l (g) + A q \to H C l (a q), △ H = - 17.32 k c a l$
$A l_{2} C l_{6} (s) + A q \to A l_{2} C l_{6} (a q), △ H = - 153.69 k c a l$ .

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A l_{2} C l_{6}

2 A l (s) + 6 H C l (a q) ⟶ A l_{2} C l_{6} (a q) + 3 H_{2} + 1004.2 k J

H_{2} (g) + C l_{2} (g) ⟶ 2 H C l (g) + 184.1 k J

H C l (g) + a q ⟶ H C l (a q) + 73.2 k J

A l_{2} C l_{6} (s) + a q ⟶ A l_{2} C l_{6} (a q) + 643.1 k J

{A l}_{2} {C l}_{6}

2 A l (s) + 6 H C l (a q) ⟶ {A l}_{2} {C l}_{6} (a q) + 3 H_{2} (g), Δ H = - 239.76 k c a l

H_{2} (g) + {C l}_{2} (g) ⟶ 2 H C l (g); Δ H = - 44.0 k c a l

H C l (g) + A q ⟶ H C l (a q); Δ H = - 17.32 k c a l

{A l}_{2} {C l}_{6} (s) + A q ⟶ {A l}_{2} {C l}_{6} (a q); Δ H = - 153.69 k c a l

△ H_{f}^{\circ}

\frac{1}{2} H_{2} (g) + \frac{1}{2} C l_{2} (g) \to H C l (g); △ H_{f}^{\circ} = - 92.4 k J

H C l (g) + n H_{2} O \to H^{+} (a q) + C l^{-} (a q); △ H^{\circ} = - 74.8 k J

△ H_{f}^{\circ} H^{+} (a q) = 0.0 k J

2 A l (s) + 6 H C l (a q) \to 2 A l^{3 +} (a q .) + 6 C l^{-} (a q .) + 3 H_{2} (g)

2 A l (s) + 6 H C l (a q) \to 2 A l^{3 +} (a q) + 6 C l^{-} (a q) + 3 H_{2} (g)

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