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Question

Calculate the heat of hydrogenation of C2H2 to C2H4
H2(g)+12O2(g)H2O(l);ΔH=68.32 kcal
C2H2(g)+12O2(g)2CO2(g)+H2O(l);ΔH=310.61 kcal
C2H4(g)+32O2(g)2CO2(g)+2H2O(l);ΔH=337.32 kcal

A
-51.46 kcal
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B
-41.46 kcal
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C
81.46 kcal
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D
41.46 cal
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Solution

The correct option is B -41.46 kcal
Given,
H2(g)+12O2(g)H2O(l);ΔfH=68.32 kcal
C2H2(g)+12O2(g)2CO2(g)+H2O(l);ΔcombH=310.61 kcal
C2H4(g)+32O2(g)2CO2(g)+H2O(l);ΔcombH=337.32 kcal
Heat of hydrogenation=heat of formation of water +heat of combustion of C2H2 - heat of combustion of C2H4
Heat of hydrogenation=ΔfH(H2O)+ΔcombH(C2H2(g))-ΔcombH(C2H4(g))
Heat of hydrogenation=(-68.32 - 310.61 + 337.32) kcal
Heat of hydrogenation= 41.61 kcal

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